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Average Questions in Maths PDF – Download Here!!!!

Average 

The average height of the first six students is 170 cm, the average height of the last eight students is 175 cm. The average height of the total 16 students is 180 cm. Find the average height of the rest two students.

  1. 210 cm
  2. 250 cm
  3. 240 cm
  4. 230 cm
  5. 260 cm
  1. Correct option is : D 

Solution: 

Sum of the heights of the first six students = 170 × 6 = 1020 cm Sum of the heights of the last eight students = 175 × 8 = 1400 cm Sum of the heights of the total 16 students = 180 × 16 = 2880 Sum of the height of the left 2 students = 2880 – 1020 – 1400 = 460 Average height of the left 2 students = 460 = 230 cm 2 

  1. The average salary of each trainee in an startup is Rs. 90. The average salary of 16 trainees is Rs.708.75 and the average salary of the rest is Rs. 75. How many trainees does the startup have?
  2. 670
  3. 676
  4. 682
  5. 840
  6. None of these
  1. Correct option is : B 

Solution: 

Total salary of trainees = 16 × 708.75 = Rs. 11,340 

Let there be x trainees. 

∴ Total salary = Rs. (90x) and salary of remaining trainees = Rs. [75(x − 16)] ∴ 90x = 11340 + 75x − 1200 

∴ 15x = 10140 i.e. x = 676 

  1. In a hostel, food is available for 200 students for 50 days. After 10 days, 50 more students join the hostel. For how many more days will the food last?
  2. 42 days
  3. 32 days
  4. 30 days
  5. 40 days
  6. None of these

4. The average weight of five friends P, Q, R, S, and T is (x + 6) kg while the average weight of R and T is (x – 6) kg. If the weight of another person U is also added, then average weight of all of them is reduced by 5 kg. Find the value of ‘x’ if average weight of P, Q, S and U is 94.5 kg. 

  1. 74
  2. 80
  3. 84
  4. 90
  5. 94
  1. A, B, C, D and E are five persons. The weight of A, B and C is 90%, 112% and 94% respectively of the average weight of all five. The ratio of weight of D and E is 6 : 11. The difference between the weight of D and E is 75kg. What is the average weight of al the five persons?
  1. 74
  2. 80
  3. 84
  4. 90
  5. 94
  1. The average age of girls in the class is 15 years. The average age of boys in the class also added, then the average becomes 18. If there are 18 boys in the class and the average age of boys in the class is 20, then find how many girls in the class?
  1. Correct option is : B

Solution: 

Man days for which food is available = 200 × 50 = 10000 

Available food is enough for 1 student for 10000 days 

Food used by 200 students in 10 days = 200 × 10 man days of food = 2000 Man days of food left = 10000 – 2000 = 8000 man days of food Total number of students now = 200 + 50 = 250 

Remaining food can be used for 250 students for 

=8000 days = 32 days 250 

  1. The average marks of Raji in a certain examination is 85. If she got 20 more marks in Maths and 12 more marks in English, then the average becomes 89. Find the total number of subjects she studied?
  1. Correct option is : D

Solution:  

Total weight of friends P, Q, R, S and T = (x + 6) x 5 = 5 (x + 6) kg So, total weight of P, Q and S = 5 (x + 6) – 2 (x – 6) = (3x + 42) = 3 (x + 14) Weight of U = (x + 6 – 5) × 6 – 5 (x + 6) = 6 (x + 1) – 5 (x + 6) = (x – 24) kg According to the question, 

[3 (x + 14) + (x – 24)] = 94.5 × 4 

4x + 18 = 378 

4x = 360; x = 90

  1. Correct option is : E

Solution: 

Let the average weight of all five = 100k 

So, weight of A = 90k, B = 112k and C = 94k Let the weight of D = d and that of E = e 

90k + 112k + 94k + d + e = 100k 5 

d + e = 204k 

d : e = 6 : 11 → d = 6× 204 = 72k → e = 132k 17 Difference = 132k – 72k = 60k 

60k = 75 

So, k = 75 = 1.25 60 

Average weight of all the five persons = 100 * 1.25 = 125kg 

  1. The average salary of the whole employees in a company is Rs. 300 per day. The average salary of officers is Rs. 800 per day and that of clerks is Rs. 240 per day. If the number of officers is 30, then find the number of clerks in the company?
  1. Correct option is : C

Solution: 

Let the total number of girls in the class be x,  15x + (20*18) = (x+18)*18  

15x+360 = 18x+324 

36 = 3x  

X =12  

Total girls in the class is 12 

 

  1. The average salary of the whole employees in a company is Rs. 300 per day. The average salary of officers is Rs. 800 per day and that of clerks is Rs. 240 per day. If the number of officers is 30, then find the number of clerks in the company?
  1. Correct option is: A 

Solution: 

Let the total number of subjects be x,  

Average = Sum/n  

(85x + 20 + 12)/x = 89  

85x + 32 = 89x  

4x = 32  

X = 8  

Total number of subjects = 8 

  1. Correct option is : D 

Solution:

Let the number of clerks in the company be x,  

800*30 + 240*x = 300(30 + x)  

24000 + 240x = 9000 + 300x  

15000 = 60x  

X = 15000/60 = 250  

Total number of clerks in the company = 250 

The average age of 25 students in a class is 20. If the age of a teacher is included, then the average age increased by one year, find the age of the teacher?

  1. Correct option is : B 

Solution: 

Total age of 25 students = 25*20 = 500  

Total age of 25 students and teacher = 26*21 = 546  Age of the teacher= 546 – 500 = 46 years  

Shortcut:  

N Average  

25 20  

26 21  

If both n and Average increased by 1, then the age of the teacher is,  = > (25 + 21) or (26 + 20) = 46 years

  1. The average height of 20 students is 105 cm. But later it was found that, the heights of 2 students were wrongly entered as 75 instead of 68 and 91 instead of 108. Then find the correct average?
  1. Correct option is : C 

Solution: 

Correct Average = [(20*105) – (75 + 91) + (68 + 108)]/20  = > 105.5 cm 

  1. The Average marks obtained by 45 students in an examination is 12. If the average marks of passed students are 14 and that of failed students are 5, then find the number of students who passed the examination?
  1. Correct option is : A 

Solution: 

Let the number of passed students be x,  

45*12 = 14x + (45 – x)*5  

540 = 14x + 225 – 5x  

540 – 225 = 9x  

9x = 315  

X = 35  

  1. The average weight of 20 people is increased by 2.2 kg when one man weight 53 kg is replaced by another man. Find the weight of new man?

Total number of passed students = 35 

  1. Correct option is : D 

Solution: 

Average = 2.2, Number of people (n) = 20  

Average = Total sum/n

Total weight increased = 2.2*20 = 44 kg  

Weight of new man = 44 + 53 = 97 kg 

  1. Average number of sweets distributed in a class of 52 students is 5. If some number of students newly joined in the class and the average becomes 4, then find the number of newly joined students?
  1. Correct option is : B 

Solution: 

Let the number of newly joined students be x,  

According to the question,  

52*5 = (52 + x)*4  

260 = 208 + 4x  

52 = 4x  

X = (52/4) = 13 

  1. The average weight of 50 students in a class is 60 kg. The weights of two students were wrongly entered as 74 kg and 66 kg instead of 66 kg and 54 kg respectively. Find the corrected average weight of the class?
  1. Correct option is : C 

Solution: 

Total weight of 50 students = 50*60  

New weight = (50*60) – 74 – 66 + 66 + 54 = (50*60) – 20  New average = (3000 – 20)/50 = 59.60 kg 

  1. The average of 5 numbers is 120. The average of the first two numbers is 125 and the average of the last two numbers is 130. What is the third number?
  1. Correct option is : A 

Solution: 

Sum of 5 numbers = 120*5 = 600  

Sum of first two numbers = 125*2 = 250  

Sum of last two numbers = 130*2 = 260 Third number = 600 – (250 + 260)  = > 600 – 510 = 90 

The average weight of 39 Students in a class is 23. Among them Sita is the heaviest while Tina is the lightest. If both of them are excluded from the class still the average remains same. The ratio of weight of Sita to Tina is 15:8.Then what is the weight of the Tina?

  1. Correct option is : B

Solution: 

S+T = 23*(39-37) = 46 

S/T = 15/8 

T = 16 

There are 459 students in a hostel. If the number of students increased by 36, the expenses of the mess increased by Rs .81 Per day while the average expenditure per head reduced by 1. Find the original expenditure of the mess?

  1. Correct option is : E

Solution: 

Total expenditure = 459x 

36 students joined then total expenditure = 459x+81 

average = (459x+81)/495 = x-1 

x = 16 

original expenditure = 16*459 = 7344 

The average weight of 40 Students is 32. If the Heaviest and Lightest are excluded the average weight reduces by 1. If only the Heaviest is excluded then the average is 31. Then what is the weight of the Lightest?

  1. Correct option is : B

Solution: 

40*32 = 1280 

(1280-H)/39 = 31 

H =71 

(1280-71- L)/38 = 31 

L = 31 

. Average marks obtained in English by 17 girls of a class is 35. The marks obtained by them is arranged in ascending order form and in Arithmetic progression. If the marks obtained by the 2nd, 6th, 9th, 12th and 16th position are removed from the table, then find the new average of marks obtained by the remaining girls in English.  

  1. Correct option is : B 

Solution: 

Total marks obtained by 17 girls = 35 × 17 = 595 

Let the marks obtained by 17 girls be(in ascending order) be: 

(a – 8d) , (a – 7d) , (a – 6d) , (a – 5d) , (a – 4d) , (a – 3d) , (a – 2d) , (a – d), (a) (a +  d) , (a + 2d) , (a + 3d) , (a + 4d) , (a + 5d) , (a + 6d) , (a + 7d) , (a + 8d) A = 35 

Sum of 2nd, 6th, 9th, 12th and 16th term = 5a =175 

New average = 595 – 175=420 = 35 

12 12 

Average marks of group of students is 48. Out of these, 3 students with marks 43, 68 and 51 are removed and a new student with a score of 84 is added to the list. If the number of students in the group was 8, then find the percentage increase in the average marks with respect to the initial average?

  1. Correct option is : A 

Solution: 

Let the sum of the marks of the unchanged 5 students from initial tally be equal to  ‘x’, such that, 

x + 43 + 68 + 51 = 48 (Given) 8 

Then, 

x = 384 – (43 + 68 + 51) = 384 – 162 = 222 

With adding of a new student marks, 

Sum of marks of 6 students becomes = x + 84 = 222 + 84 = 306 New Average = 306 = 51 6 

Percentage increase in average = 51 – 48 × 100 48 

=300=100 = 6.25% 48 16 

  1. ‘N’ is the number employees in a Bengaluru based IT company. The average age of employees working in the company is 35 years. What will be the average age of these employees in next two years when 10 employees will retire. Given that, retirement age is 60 years and N = 40.
  1. Correct option is : E

Solution:

Total employees in the company = 40 

Average age of employees = 35 

Total age of employees = (40 × 35) = 1400 

In next two years, 

Total remaining employees = 40 – 10 = 30 

Retirement age = 60 years 

Total age of 30 employees after 2 years = 1400 + (40 × 2) – (60 × 10) = 1400 + 80 – 600 = 880 

∴ Average age after two years = 880=88years 30 3 

  1. Rajiv decided to go for a dinner with his 12 friends. He paid Rs. 145 and each of his friends paid some equal amount. They later found out that the average amount that should be paid by all of them was 5 more than what was actually paid by each of his friends. How much money did each of his friend pay?
  1. Correct option is : A 

Solution: 

Let the amount paid by each of Rajiv’s friend be Rs x 

Total amount paid by them in all = Rs. (145 + 12x) 

Average amount that should have been paid by Rajiv’s friends = 5 + x 145 + 12x = (x + 5) 13 

x = 80 

  1. A family has 5 members, Father, mother and their three children. The average age of family immediately after the birth of first, second and third child was 16, 15.75 and 14.2 years respectively. What is the age of elder child, if the present age of entire family is 15.2 years? 
  1. Correct option is : C 

Solution: 

Let the present age of father, mother and three children’s be F, M, C1, C2 and C3. When the first child was born, the age of the first child was 0. 

Average = 16 sum of their age = 16×3 =48 

After n1 years, second child was born, the age of first child will be n1 years and age  of second child be 0. 

Average = 15.75, sum of their age = 15.75 × 4 = 63 

Difference between the sum of their age after n1 years = 63 – 48 = 15 3n1 = 15 

n1 = 5 

After n2 years, third child was born, the age of first child get increased by n2 years,  age of second child will be n2 years, age of third child is 0. 

Average = 14.2, sum of their age = 14.2 x 5 = 71 

Difference between the sum of their age after n2 years = 71 – 63 = 8 4n2 = 8 

n2 = 2 

After n3 years, average is 15.2 years, sum of their age = 15.2 × 5 = 76 Difference between the sum of their age after n3 years = 76 – 71 = 5

5n3 = 5 

n3 = 1 

First child was born 1 + 2 + 5 = 8 years ago. 

So the age of the first child is 8 years. 

  1. In an exam of 100 marks, the average marks of a class of 40 students are 76. If the top 3 scorers of the class leave, the average score falls “down by 1. If the other two toppers except “the highest topper scored not more than 85. “then what is the minimum score the topper can score?
  1. Correct option is : C

Solution: 

Total score of 40 students = (40 × 76) = 3040 

Total score of top 3 scorers = 3040 – (37 × 75) = 265 

To minimize the score of the top scorer, we assume the other two top scorers score  the maximum they can = 85 marks each. 

So, the top scorer scored = 265 – 170 = 95 marks. 

  1. Average weight of three friends Amar, Visera and Daman is 70 kg. Another person Vishal joins the group and now the average is 66 kg. If another person Tahir whose weight is 6 kg more than Vishal, joins the group replacing Amar, then average weight of Visera, Daman, Vishal and Tahir becomes 75 kg. What is the weight of Amar (in kg)?
  1. Correct option is : D 

Solution: 

Total weight of Amar, Visera and Daman = 70 × 3 = 210 kg 

Again, Amar + Visera + Daman + Vishal = 66 × 4 = 264 kg ……… (i) ∴ Weight of Vishal = 264 – 210 = 54 kg 

∴ Weight of Tahir = 54 + 6 = 60 kg 

Now, as per the question 

Visera + Daman + Vishal + Tahir = 75 × 4 = 300 kg. ………………. (ii) Subtracting (i) from (ii), we get 

Tahir – Amar = 60 – Amar = 300 – 264 = 36 

Therefore, weight of Amar = 60 – 36 = 24 kg 

  1. The average salary of a company increases by 100 when the salary of the manager, which is Rs. 9500, is included. If the number of employees excluding the manager is the smallest cube divisible by 16, what is the final average of the company?
  1. Correct option is : D 

Solution: 

The smallest cube divisible by 16 is 64. 

Let’s assume the average salary before the manager’s salary is included is x After addition of Manager’s salary the average increases by 100 We can write down the above information in form of an equation as: 64x + 9500 = 65 × (x + 100) 

Solving for x, we get x = 3000 

The final average is 3000 + 100 = Rs. 3100 

  1. In Champions league, Rohit scored an average of 120 runs per match in the first 3 match and an average of 140 runs per match in the last four match. What is Rohit’s average runs for the first match and the last two match if his average runs per match for all the five match is 122 and total number of matches are 5? 
  1. Correct option is : A 

Solution: 

Rohit’s average score in the first 3 exams = 120 

Let the scores in the 5 exams be denoted by M1, M2, M3, M4, and M5

M1 + M2 + M3 = 120 × 3 = 360 …….(i) 

Average of last 4 match = 140 

⇒M2 + M3 + M4 + M5 = 140 4 

⇒ M2 + M3 + M4 + M5 = 560 ……(ii) 

Average of all the exams 

⇒M1 + M2 + M3 + M4 + M5 = 122 5 

∴ M1 + M2 + M3 + M4 + M5 = 122 × 5 = 610 …….(iii) From solving above equation, we get M1 + M4 + M5 = 300 

Required average runs = 300 = 100 3 

  1. The average of 9 persons age is 63. The average of 3 of them is 58, while the average of the other 3 is 60. What is the average of the remaining 3 numbers?
  1. Correct option is : B 

Solution: 

Sum of the remaining 3 numbers = [(9*63) – [(3*58)+(3*60)]]  =567 – (174+180)  

=567 – 354  

=213  

Required average = 213 / 3 

=71 

  1. A museum has an average of 820 viewers on Saturdays and 460 on other days. The average no. of viewers per day in a month of 30 days beginning with a Saturday is.
  1. Correct option is : A

Solution: 

Since the month begins with a Saturday, so there will be 5 Saturday in the month.  Required average = ((820*5) + (460*25) / 30)  

= (4100+11500)/30  

=15600 / 30  

= 520  

The average no. of viewers per day in a month is 520 

  1. In Santhosh opinion, his weight is greater than 54kg but less than 63 kg. His brother does not agree with Santhosh and he thinks Santhosh’s weight is greater than 50kg but less than 60kg. His father’s view is that his weight cannot be greater than 57kg. If all of them are correct in their estimation, what is the average of different portable weights of Santhosh?
  1. Correct option is : C 

Solution: 

Let Santhosh’s weight be y kg  

According to Santhosh 54<y<63 

According to Santhosh brother 50<y<60 

According to Santhosh father y<57 

The value satisfying all the above conditions are 55, 56 and 57 Required average = 56 kg

  1. The average of 6 consecutive even numbers is 41. Find the largest of these numbers?
  1. Correct option is : C 

Solution: 

Let the numbers be x, x+2, x+4, x+6, x+8 and x+10  

Then, (x + x+2 + x+4 + x+6 + x+8 + x+10) / 6 = 41  

6x + 30 = 246  

6x = 246 – 30  

6x = 216  

X = 216 / 6  

X= 36  

Therefore largest number = x+10 = 36+10  

Largest number = 46 

  1. If the average of 5 observations x, x+1, x+2, x+3 and x+4 is 24, then the average of last 2 observations is?
  1. Correct option is : D 

Solution: 

We have (x+x+1+x+2+x+3+X+4) / 5 = 24  

5x +10 = 24*5  

5x +10 = 120  

5x = 110  

X = 110 / 5  

X= 22 

So the numbers are 22, 23, 24, 25 & 26  

Required average = (25+26) /2  

=51/2  

=25.5  

Therefore average of last 2 observations is 25.5 

  1. 8 candidates are to be divided into 2 groups P & Q of 5 & 3 candidates. The average percent mark obtained by the candidate of group P is 32 and the average percent marks of all the 8 candidate is 35. What is the average percentage of marks of candidate of group Q?
  1. Correct option is : C 

Solution: 

Required average = [(35*8) – (32*5)]/ 3  

= [280 – 160]/ 3  

= 120/ 3 

= 40  

The average percent marks of candidates of group Q is 40. 

  1. In a certain camp, there are 30 girls whose average age is decreased by 6 months, when one girl aged 27 yrs is replaced by a new girl. Find the age of the new girl.
  1. Correct option is : D 

Solution: 

Average age of new person= age of removed person – no of persons*decrease in  age  

Average age of new person =27 – 30*(6/12) 

= 27 – 30(1/2)  

= 27 – 15  

= 12 years  

Hence the age of the new girl is 12 years 

  1. A batsman has completed 15 innings and his average is 22 runs. How many runs must he make in his next innings so as to raise his average to 26?
  1. Correct option is : C 

Solution: 

Total runs of 15 innings = 22*15  

=330 runs  

Suppose he needs a score of x in 16th innings,  

Then average in 16th innings = (330+x) /16  

(330+x) /16 = 26  

330+x = 16*26 

330+x = 416  

X = 416-330  

X = 86  

He needs a score of 86 runs in 16th innings 

36. The average expenditure of Sharma for the January to June is Rs. 4200 and he spent Rs. 1200 in January and  Rs.1500 in July. The average expenditure for the months of February to July is:

  1. Correct option is : C

Solution: 

Total Expenditure(Jan – June) = 4200 * 6 = 25200 Total Expenditure(Feb – June) = 25200 – 1200 = 24000 Total Expenditure(Feb – July) = 24000 + 1500 = 25500/6 = 4250 

  1. Correct option is : D

Solution: 

Average of First six players = 49 * 6 = 294 

Average of Last six players = 52 * 6 = 312 

Average of all players = 50 * 11 = 550 

Average weight of sixth player = 294 + 312 – 550 = 56 

37. The average weight of all the 11 players of CSK is 50 kg. If the average of first six lightest weight players of CSK is 49 kg and that of the six heaviest players of CSK is 52 kg. The average weight of the player which lies in the sixth position in the list of players when all the 11 players of CSK are arranged in the order of increasing or decreasing weights.

  1. Correct option is : C

Solution: 

32 * 3 + 30 * 4 – 26 * 6 = 96 + 120 – 156 = 60 

The average income of Arun, Bala and Chitra is Rs. 12,000 per month and average income of Bala, Chitra and David is Rs. 15,000 per month. If the average salary of David be twice that of Arun, then the average salary of Bala and Chitra is in Rs?

  1. Correct option is : D

Solution: 

Arun + Bala + Chitra = 12000*3 

Bala + Chitra + David = 15000*3 

David – Arun = 3000*3 = 9000

David = 2Arun 

David = 18000 and Arun = 9000 

Average salary of Bala and Chitra, 

= (45000-18000)/2 = 13,500 

  1. The students of a class are divided into 3 groups depending on their performance in a test – the top, middle and bottom. The top group consists of 45% of the students, the middle group consists of 30% of the students and the rest are in the bottom group. The average marks of the bottom group are 20, those of the middle are 25 while the average marks for the entire class are 26. Find the average marks of the top group.
  1. Correct option is : D

Solution: 

Top Middle Bottom Total 

Number of  student 

45 30 25 100 

Average P 25 20 26

Let the total number of students in the class = 100. The data given in the question  is shown in the table. 

Let average of top group be P 

(45 × P) + (30 × 25) + (20 × 25) = (100 × 26) 

⇒ P = 30 

The average height of girls in a class is 5 ft and that of boys is 5.7 ft. If the average height of the students in class is 5.5 ft what could be the possible strength of boys and girls respectively in the class:

  1. Correct option is : C

Solution: 

Let number of boys be B and 

number of girls be G in the class 

so total strength of class = B + G 

If the average height of boys in class is 5.7 ft then total height of boys in class will  be 5.7B 

similarly If the average height of girls in class is 5 ft then total height of girls in  class will be 5G 

ALSO given average height of all students in class is 5.5ft then 7.5B + 5G = 5.5 B + G 

⇒ 5.7B + 5G = 5.5B + 5.5G 

⇒ 0.2B = 0.5G or 2B = 5G …(a) 

Now we have to choose B and G such that ….(a) gets equal 

the value at option 3 rd i.e B = 50 AND G = 20 satisfy it 

On the occasion of teacher’s day, some number of boys and girls contributed some money. The average contribution of boys was Rs. 250 and that of girls was Rs. 100. If the average contribution per student was Rs. 160 on the whole then what percent of students are boys?

  1. Correct option is : C 

Solution: 

Let the number of boys = x and the number of girls = y then 

250x + 100y = 160(x + y) 

90x = 60y 

x : y = 2 : 3 

The reqd. percentage = 2 × 100 = 40% 5 

The average number of chocolates that some number of boys have is 240 and average number of chocolates that some number of girls have is 180. If each of the boys eat 10 chocolates then the average number of chocolates with all the students become 200. The total number of boys is what percentage of the total number of students?

  1. Correct option is : B

Solution: 

Let the number of boys = x and the number of girls = y 

The total number of chocolates the boys have = 240x 

The total number of chocolates the girls have = 180y 

If each of the boys eat 10 chocolates then the remaining number of chocolates, the  boys will have = 240x – 10x = 230x 

The sum of the all the chocolates = 200(x + y) = 230x + 180y 

20y = 30x 

x : y = 2 : 3 

The reqd. percentage = 2 × 100 = 40% 5 

In a class with a certain number of students if one new student weighing 50 kg is added, then average weight of class is increased by 1 kg. If one more student weighing 50 kg is added, then the average weight of the class increases by 1.5 kg over the original average. What is the original average weight (in kg) of the class?

  1. Correct option is : D

Solution: 

Let x be the number of students in the class and y be the average weight of the  class 

Now according to question, 

xy + 50 = y + 1 x + 1 

x + y = 49 ………. (i) Again, 

xy + 50 + 50 = y + 1.5 x + 2 

1.5x + 2y = 97 ………. (ii) From equation (i) and (ii), we get y = 47 

The average salary of male employees in a firm was Rs. 6000 and that of females was Rs. 5600. The mean salary of all the employees was Rs. 5800. What is the % of female employees?

  1. Correct option is: B

Solution: 

Average salary of male employees = Rs. 6000 

Average salary of female employees = Rs. 5600 

Mean salary = Rs. 5800 

By using alligation 

(6000) (5600) 

\ /

(5800) 

/ \ 

200 200 

∴ The ratio of male : female = 200 : 200 = 1 : 1 

Hence, % of female employees = 1× 100 = 50% 2 

The average salary of 65 workers is Rs. 5680 out of which average salary of 31 workers is Rs. 2356 and that of 23 workers is Rs. 4589. What is the average salary of remaining workers?(value in approximate)

  1. Correct option is : C 

Solution: 

Total salary of 65 workers = 65 × 5680 = Rs. 369200 

Total salary of 31 workers = 31 × 2356 = Rs. 73036 

Total salary of 23 workers = 23 × 4589 = Rs. 105547 

No. of remaining workers = 65 – 31 – 23 = 65 – 54 = 11 

Total Salary of 11 workers = 369200 – 73036 – 105547 = 369200 – 178583 = Rs.  190617 

Required average = 190617 = 17329(approx) 11 

The average number of sweets distributed in a class of 60 students is 5. If ‘x’ number of students newly joined the class and the average becomes 4, and then find the newly joined students in the class?

  1. Correct option is : B 

Solution: 

Let newly joined students be x,  

According to the question,  

60*5 = (60 + x)*4 

300 = 240 + 4x  

60 = 4x  

X = 15  

The newly joined students in the class = 15 

  1. 4 years ago, the average age of the family of 5 members is 23 years. A baby is born now; the average age of the family is same as before. Find the age of the baby?
  1. Correct option is : D 

Solution: 

The total present age of the family of 5 members = (23*5) + (4*5) = 135  A baby is born now; the average age of the family is same as before.  The total present age of the family of 6 members (Including the baby)  = > 23*6 = 138  

The age of the baby = 138 – 135 = 3 years 

  1. The average age of 25 students and teacher is 15 years. If the age of the teacher is excluded, then the average is decreased by one year. Find the age of the teacher?
  1. Correct option is : A 

Solution: 

Total age of 25 students and teacher = 26*15 = 390  

Total age of 25 students = 25*14 = 350 

The age of the teacher = 390 – 350 = 40 

  1. The average marks obtained by 240 candidates in a certain examination is 70. If the average marks of passed candidates is 78 and that of failed candidates is 30, then find the total no of passed candidates in the examination?
  1. Correct option is : C 

Solution: 

Let passed candidates be x, 

So, Failed candidates = 240 – x  

Total marks,  

(240*70) = 78x + (240 – x)*30  

16800 = 78x + 7200 – 30x  

9600 = 48x  

X= 9600/48 = 200  

Total no of passed candidates in the examination is 200. 

  1. The average marks scored by 12 students is 73. If the scores of Ajay, Akhil and Alok are included, the average becomes 73.6. If Ajay scored 68 marks and Alok scored 6 more marks than Akhil, then find the marks scored by Akhil.
  1. Correct option is : D 

Solution: 

The average marks scored by 12 students = 73  

Total marks scored by 12 students = (73*12) = 876  

If the scores of Ajay, Akhil and Alok are included, the average becomes 73.6  Total marks scored by 15 students = (73.6*15) = 1104  

The scores of Ajay, Akhil and Alok = 1104 – 876 = 228  

Ajay = 68 marks, Alok = Akhil + 6  

Alok – Akhil = 6 –à ……………(1)  

Alok + Akhil = 160-à …………..(2)  

Solving (1) and (2),  

Alok = 83  

Akhil = 77 marks 

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